Given f(x)=9x45−2x57f(x)=9x^{\frac{4}{5}}-2x^{\frac{5}{7}}f(x)=9x54−2x75 then;
f′(x)=365x−15−107x−27=365x15−107x27f'(x)=\frac{36}{5}x^{-\frac{1}{5}}-\frac{10}{7}x^{-\frac{2}{7}}=\frac{36}{5x^{\frac{1}{5}}}-\frac{10}{7x^{\frac{2}{7}}}f′(x)=536x−51−710x−72=5x5136−7x7210
f′(x)=365x15−107x27f'(x)=\frac{36}{5x^{\frac{1}{5}}}-\frac{10}{7x^{\frac{2}{7}}}f′(x)=5x5136−7x7210 .
Then
f′(3)=365(3)15−107(3)27≈4.736025022f'(3)=\frac{36}{5(3)^{\frac{1}{5}}}-\frac{10}{7(3)^{\frac{2}{7}}} \approx4.736025022f′(3)=5(3)5136−7(3)7210≈4.736025022
f′(6)=365(6)15−107(6)27≈4.175359577f'(6)=\frac{36}{5(6)^{\frac{1}{5}}}-\frac{10}{7(6)^{\frac{2}{7}}} \approx 4.175359577f′(6)=5(6)5136−7(6)7210≈4.175359577
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