Question #142801

Suppose that f(x)=9x4/5−2x5/7. Evaluate each of the following:


f′(3) =


f′(6) =

Expert's answer

Given f(x)=9x452x57f(x)=9x^{\frac{4}{5}}-2x^{\frac{5}{7}} then;


f(x)=365x15107x27=365x15107x27f'(x)=\frac{36}{5}x^{-\frac{1}{5}}-\frac{10}{7}x^{-\frac{2}{7}}=\frac{36}{5x^{\frac{1}{5}}}-\frac{10}{7x^{\frac{2}{7}}}


f(x)=365x15107x27f'(x)=\frac{36}{5x^{\frac{1}{5}}}-\frac{10}{7x^{\frac{2}{7}}} .


Then


f(3)=365(3)15107(3)274.736025022f'(3)=\frac{36}{5(3)^{\frac{1}{5}}}-\frac{10}{7(3)^{\frac{2}{7}}} \approx4.736025022


f(6)=365(6)15107(6)274.175359577f'(6)=\frac{36}{5(6)^{\frac{1}{5}}}-\frac{10}{7(6)^{\frac{2}{7}}} \approx 4.175359577


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