Question #142091
Evaluate the iterated integral ∫(0 to 1)∫(x to 5x)∫(0 to y) 5xyz dzdydx.
1
Expert's answer
2020-11-09T15:32:41-0500

01x5x0y5xyzdzdydx\int_0^1 \int_x^{5x} \int_0^y 5xyz dzdydx


Go from inside to outside


1.0y5xyzdz=5xy[z2/2]0y=5/2xy31. \int_{0}^{y} 5xyz dz = 5xy\Big[z^2/2\Big]_0^y = 5/2xy^3


2.x5x5/2xy3dy=5/2x[y4/4]x5x=5/2x(625x4/4x4/4)=390x52. \int_{x}^{5x} 5/2xy^3 dy = 5/2 x\Big[y^4/4\Big]_x^{5x} = 5/2x(625x^4/4 - x^4/4) = 390x^5


3.01390x5dx=390x6/601=653. \int_0^1 390x^5 dx = 390x^6/6\Big|_0^1 = 65


Answer: 01x5x0y5xyzdzdydx=65\int_0^1 \int_x^{5x} \int_0^y 5xyz dzdydx = 65


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