Answer to Question #141467 in Calculus for Vanessa Samson

Question

A wound is healing in such a way that t days since Monday, the area of the wound has been decreasing at a rate of -3(t+2)^-2 sq cm per day. If on Tuesday, the area of the wound was 2 sq cm, what was the area of the wound on Monday?

Answer 1

$f(t) =-\frac{3}{(t+2)^2}$

$f(tuesday) = f(1) = -\frac{3}{(1+2)^2}=-\frac{1}{3}$

On Tuesday the wound was 2 sq sm and decreased at 1/3 sq sm since Monday.

Therefore on Monday the wound was:

$2+\frac{1}{3}=2.33 sm^2$