Question #141467
A wound is healing in such a way that t days since Monday, the area of the wound has been decreasing at a rate of -3(t+2)^-2 sq cm per day. If on Tuesday, the area of the wound was 2 sq cm, what was the area of the wound on Monday?
1
Expert's answer
2020-11-02T14:40:42-0500

f(t)=3(t+2)2f(t) =-\frac{3}{(t+2)^2}

f(tuesday)=f(1)=3(1+2)2=13f(tuesday) = f(1) = -\frac{3}{(1+2)^2}=-\frac{1}{3}

On Tuesday the wound was 2 sq sm and decreased at 1/3 sq sm since Monday.

Therefore on Monday the wound was:

2+13=2.33sm22+\frac{1}{3}=2.33 sm^2



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