f(t)=−3(t+2)2f(t) =-\frac{3}{(t+2)^2}f(t)=−(t+2)23
f(tuesday)=f(1)=−3(1+2)2=−13f(tuesday) = f(1) = -\frac{3}{(1+2)^2}=-\frac{1}{3}f(tuesday)=f(1)=−(1+2)23=−31
On Tuesday the wound was 2 sq sm and decreased at 1/3 sq sm since Monday.
Therefore on Monday the wound was:
2+13=2.33sm22+\frac{1}{3}=2.33 sm^22+31=2.33sm2
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