Question #141175

If f(x,y,z)=(x2y2−2y3z2−4x3z2+xyz) , the gradient of f at (1,−2,−1) is

Expert's answer

fx=2xy212x2z2+yz.\frac{\partial f}{\partial x}=2xy^2-12x^2z^2+yz.

fy=2x2y6y2z2+xz.\frac{\partial f}{\partial y}=2x^2y-6y^2z^2+xz.

fz=4y3z8x3z+xy.\frac{\partial f}{\partial z}=-4y^3z-8x^3z+xy.

At the point (1,-2,-1): fx=6,  fy=29,  fz=26.\frac{\partial f}{\partial x}=-6, \;\frac{\partial f}{\partial y}=-29,\; \frac{\partial f}{\partial z}=-26.

Gradient: =[6,29,26].\nabla =[-6,-29,-26].


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