Question #140444

Find Fourier integral of š‘“(š‘„) = š»(š‘„ āˆ’ 1) āˆ’ š»(š‘„ āˆ’ 2)


Expert's answer

12Ļ€āˆ«āˆ’āˆžāˆž(H(tāˆ’1)āˆ’H(tāˆ’2))eiwtdt=\dfrac{1}{\sqrt{2\pi}}\displaystyle\int_{-\infin}^\infin(H(t-1)-H(t-2))e^{iwt}dt=

=12πΓ(w)+ieiw2Ļ€wāˆ’(12πΓ(w)+ie2iw2Ļ€w)==\dfrac{1}{\sqrt{2\pi}}\delta(w)+\dfrac{ie^{iw}}{\sqrt{2\pi }w}-\big(\dfrac{1}{\sqrt{2\pi}}\delta(w)+\dfrac{ie^{2iw}}{\sqrt{2\pi }w}\big)=

=ieiw(1āˆ’ieiw)2Ļ€w=\dfrac{ie^{iw}(1-ie^{iw})}{\sqrt{2\pi }w}



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