∫(x2+7)dx=∫(x2)dx+7∫(dx)=x3/3+7x+const\intop(x^2+7)dx=\intop(x^2)dx+7\intop(dx)=x^3/3+7x+const∫(x2+7)dx=∫(x2)dx+7∫(dx)=x3/3+7x+const
the integral was presented as the sum of the table integrals. The option C is correct.
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