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Answer to Question #138057 in Calculus for oliver
Question #138057
∫ (10׳ - 2sec²x) dx
Expert's answer
"\\intop" (10x3-2sec2(x))dx = "\\intop" (10x3-2/cos2(x))dx ="\\intop" 10x3dx -2"\\intop" 1/cos2(x))dx =
=2.5x4 -2sin(x)/cos(x) + C
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