Question #138057
∫ (10׳ - 2sec²x) dx
1
Expert's answer
2020-10-13T18:53:58-0400

∫\intop (10x3-2sec2(x))dx = ∫\intop (10x3-2/cos2(x))dx =∫\intop 10x3dx -2∫\intop 1/cos2(x))dx =


=2.5x4 -2sin(x)/cos(x) + C


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