Question #138054
solve the following question with step by step.

∫∫ 2xy dxdy
1
Expert's answer
2020-10-13T15:23:24-0400

2xydxdy\large\iint2xy\,dx\,dy =


(2xydy)dx\large\int(\int2xy\,dy)dx =


((2×x×y1+12)+c1)dx\large\int((2\times x\times\dfrac{y^{1+1}}{2})+c_1)dx =


(xy2+c1)dx\large\int (xy^2+c_1)dx =


xy2+c1dx\large\int xy^2+c_1\,\,dx =


xy2dx+c1dx\large\int xy^2\,dx+\int c_1\,dx =


(xy2dx)+(c1dx)\large(\int xy^2\,dx)+(c_1\int dx) =


(x1+12×y2)+(c1×x)+c2\large(\dfrac{x^{1+1}}{2} \times y^2 ) +(c_1\times x) + c_2 =


x2y22+c1x+c2\large\dfrac{x^2y^2}{2} \, + c_1x+c_2



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