Answer to Question #137304 in Calculus for Sarita bartwal

Question

Find the domain and range of the function
f(x)=1/2-sin3x

Answer 1

We can calculate value $f(x)=\frac{1}{2}-\sin{3x}$ for every value of $x$, so domain of function is $(-\infty, +\infty)$. The range of $(-\sin{3x})$ is $[-1, 1]$, and if we add $\frac{1}{2}$ ,

range of $f(x)$ is $[-\frac{1}{2}, 1\frac{1}{2}]$ .