Let x be the length of the side of the square base a h the height of the parallelepiped
then volume
"V=x*x*h"
S =600 total surface area
"S = 2*x^2 + 4*x*h"
"h = \\frac{S-2*x^2}{4*x} = \\frac{600-2*x^2}{4*x}"
"V = \\frac{600-2*x^2}{4*x} *x^2 = 150*x -\\frac{x^3}{2}"
for x = 5 cm V = 150*5 -125/2 = 687.5 cm3
Answer : "V = 150*x -\\frac{x^3}{2}" ; for x = 5 cm V = 150*5 -125/2 = 687.5 cm3
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