Let x be the length of the side of the square base a h the height of the parallelepiped
then volume
V=x∗x∗h
S =600 total surface area
S=2∗x2+4∗x∗h
h=4∗xS−2∗x2=4∗x600−2∗x2
V=4∗x600−2∗x2∗x2=150∗x−2x3
for x = 5 cm V = 150*5 -125/2 = 687.5 cm3
Answer : V=150∗x−2x3 ; for x = 5 cm V = 150*5 -125/2 = 687.5 cm3
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