Question #132621
\int 2^{2x}\cdot 5^x dx
1
Expert's answer
2020-09-17T14:00:06-0400

22x5x=4x5x=20x2^{2x}\cdot 5^x=4^x\cdot 5^x=20^x

22x5xdx=20xdx=exln20dx=\int 2^{2x}\cdot 5^xdx=\int 20^xdx=\int e^{x\ln 20}dx=

=1ln20exln20d(xln20)=1ln20exln20+C==\frac{1}{\ln 20}\int e^{x\ln 20}d(x\ln 20)=\frac{1}{\ln 20}e^{x\ln 20}+C=

=1ln2020x+C=\frac{1}{\ln 20}20^x+C

Answer: 1ln2020x+C\frac{1}{\ln 20}20^x+C


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