Question #132619
\int 3^{x+1} dx
1
Expert's answer
2020-09-16T17:54:05-0400

3x+1dx=e(x+1)ln3dx=e(x+1)ln3d(x+1)=\int 3^{x+1}dx=\int e^{(x+1)\ln 3}dx=\int e^{(x+1)\ln 3}d(x+1)=

=1ln3e(x+1)ln3d((x+1)ln3)=1ln3e(x+1)ln3+C==\frac{1}{\ln 3}\int e^{(x+1)\ln 3}d((x+1)\ln 3)=\frac{1}{\ln 3}e^{(x+1)\ln 3}+C=

=1ln33x+1+C=\frac{1}{\ln 3}3^{x+1}+C

Answer: 1ln33x+1+C\frac{1}{\ln 3}3^{x+1}+C


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