Question #132615
\int \:\frac{x^2+1}{x^2}dx
1
Expert's answer
2020-09-14T18:10:25-0400
x2+1x2dx=dx+1x2dx=x1x+C\int\dfrac{x^2+1}{x^2}dx=\int dx+\int\dfrac{1}{x^2}dx=x-\dfrac{1}{x}+C


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