Question

∫ 4u^{\frac{3}{4}}du

Answer 1

Solution. Find the integral

$$\intop 4u^{\frac{3}{4}}du=\frac{16u^{\frac{7}{4}}}{7}+C$$

where C is constant.

Answer.

$$\intop 4u^{\frac{3}{4}}du=\frac{16u^{\frac{7}{4}}}{7}+C$$