Answer to Question #131424 in Calculus for G-nojay

Question #131424
g(x)=0.5∣x+2∣
1
Expert's answer
2020-09-01T16:12:49-0400

Given g(x)=0.5|x+2|

Now,

"g(x)=\\begin{cases}0.5(x+2), \\text{if} \\:x\\ge -2\\\\-0.5(x+2),\\text{if}\\: x<-2\\end{cases}"

We have to check whether g(x) is differentiable at -2.

Clearly, left hand derivative of g(x) at -2 is "g'(-2^{-})=-0.5" and right hand derivative is "g'(-2^{+})=0.5" but "g'(-2^{-})\\ne g'(-2^{+})"

Hence, g is not differentiable at -2


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