Log I = Log 10^-16 + 9....Im having trouble solving for I. I understand Log 10 to any power is that number (in this case, -16). But I still am having trouble solving for I
1
Expert's answer
2012-08-07T08:59:10-0400
Log I = Log 10^-16 + 9 As you've mentioned absolutely correctly, Log 10^-16=-16*Log 10=-16 Therefore we have Log I = Log 10^-16 + 9=-16+9=-8 So due to definition of logarithm I=10^-8
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