X=tanθ
Y=tan-1((1-tanθ )/(1+tanθ))
=tan-1((tan(π /4)-tan θ )/(1+tan( π\piπ /4)tanθ ))
=tan-1(tan(π\piπ/4-θ))
=π\piπ /4-θ,
Formula (tan(π /4))=1,
dy/dx=d/dx(π\piπ /4-tan-1x)
Answer: dy/dx=-1/(1+x2)
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