X=tanθ
Y=tan-1((1-tanθ )/(1+tanθ))
=tan-1((tan(π /4)-tan θ )/(1+tan( "\\pi" /4)tanθ ))
=tan-1(tan("\\pi"/4-θ))
="\\pi" /4-θ,
Formula (tan(π /4))=1,
dy/dx=d/dx("\\pi" /4-tan-1x)
Answer: dy/dx=-1/(1+x2)
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment