"A=\\int_0^4 (x^3+2-\\sqrt{x})dx=(\\frac{x^4}{4}+2x-\\frac{2\\sqrt{x^3}}{3})|_0^4 ="
"=(\\frac{4^4}{4}+2\\cdot 4-\\frac{2\\sqrt{4^3}}{3})-(\\frac{0^4}{4}+2\\cdot 0-\\frac{2\\sqrt{0^3}}{3})="
"=4^3+8-\\frac{16}{3}=64+8-5\\frac{1}{3}=66\\frac{2}{3}."
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