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Answer to Question #122496 in Calculus for Israel

Question #122496
differentiate y=sin^-1 [2x-1]
1
Expert's answer
2020-06-17T13:17:38-0400


we write the equation in the form y=1/sin(2x-1).

Derivative of the sine is cosine.

Derivative of the 2x is equal to 2, 

 then we get   -2cos(2x-1)/(sin(2x-1))²




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