Answer to Question #122496 in Calculus for Israel

Question #122496

differentiate y=sin^-1 [2x-1]

Expert's answer

we write the equation in the form y=1/sin(2x-1).

Derivative of the sine is cosine.

Derivative of the 2x is equal to 2,

 then we get   -2cos(2x-1)/(sin(2x-1))²

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