Answer to Question #122496 in Calculus for Israel

Question

differentiate y=sin^-1 [2x-1]

Answer 1

we write the equation in the form y=1/sin(2x-1).

Derivative of the sine is cosine.

Derivative of the 2x is equal to 2,

 then we get   -2cos(2x-1)/(sin(2x-1))²