Question #119358
The density of a semicircular plate with radius a>0 is described by ρ(x,y)=√(x^2+y^2).

The mass of the plate is
Select one:
a. (πa^3)/3


b. πa^2

c. a^3/3


d. (πa^2)/2
1
Expert's answer
2020-06-02T19:48:40-0400

The density being x2+y2\sqrt{x^2+y^2}

Let's suppose the we take a small part of the disc at a distance r from center then area of the small part will be 2πr.dr2=πrdr\frac{2\pi r.dr}{2}=\pi rdr

x=rcosθ & y=rsinθx=r\cos\theta\ \&\ y=r\sin\theta

substituting in the value of density

density = r2=r\sqrt{r^2}=r

mass = 0ar.πrdr=πa3/3_0^a\int r.\pi r dr=\pi a^3/3


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