The density being "\\sqrt{x^2+y^2}"
Let's suppose the we take a small part of the disc at a distance r from center then area of the small part will be "\\frac{2\\pi r.dr}{2}=\\pi rdr"
"x=r\\cos\\theta\\ \\&\\ y=r\\sin\\theta"
substituting in the value of density
density = "\\sqrt{r^2}=r"
mass = "_0^a\\int r.\\pi r dr=\\pi a^3\/3"
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