The density being x2+y2\sqrt{x^2+y^2}x2+y2
Let's suppose the we take a small part of the disc at a distance r from center then area of the small part will be 2πr.dr2=πrdr\frac{2\pi r.dr}{2}=\pi rdr22πr.dr=πrdr
x=rcosθ & y=rsinθx=r\cos\theta\ \&\ y=r\sin\thetax=rcosθ & y=rsinθ
substituting in the value of density
density = r2=r\sqrt{r^2}=rr2=r
mass = 0a∫r.πrdr=πa3/3_0^a\int r.\pi r dr=\pi a^3/30a∫r.πrdr=πa3/3
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments