sint:t∈(−∞,+∞),cost:t∈(−∞,+∞),ln(t+1):t+1>0→t>−1→t∈(−1,+∞)\sin t : t\in(-\infty, +\infty),\\ \cos t : t\in(-\infty, +\infty),\\ \ln(t+1): t+1>0 \to t>-1\to t\in(-1,+\infty)sint:t∈(−∞,+∞),cost:t∈(−∞,+∞),ln(t+1):t+1>0→t>−1→t∈(−1,+∞) .
The correct answer is b.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments