The position function of a particle moving along an axis given by
s(t)=t3+6t2s(t)=t^3+6t^2s(t)=t3+6t2
Then velocity given by
v(t)=dsdt=3t2+12t\begin{aligned} v(t) &=\frac{ds}{dt}\\ &= 3t^2+12t \end{aligned}v(t)=dtds=3t2+12t
Hence the acceleration given by
a(t)=dvdt=6t+12\begin{aligned} a(t) &=\frac{dv}{dt}\\ &= 6t+12 \end{aligned}a(t)=dtdv=6t+12
And the graph of acceleration
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