Question #114612

Let s(t)=t^3+6t^2 be the position function of a particle moving along an axis, where s is in metres and t is in seconds. Find the the instantaneous acceleration a(t), and show the graph of acceleration with time.

Expert's answer

The position function of a particle moving along an axis given by

s(t)=t3+6t2s(t)=t^3+6t^2

Then velocity given by

v(t)=dsdt=3t2+12t\begin{aligned} v(t) &=\frac{ds}{dt}\\ &= 3t^2+12t \end{aligned}

Hence the acceleration given by

a(t)=dvdt=6t+12\begin{aligned} a(t) &=\frac{dv}{dt}\\ &= 6t+12 \end{aligned}

And the graph of acceleration


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