A) this series is a geometric series: "a=1;q=e^{-1}" - false
B) For the geometric series "S_n=\\frac{a(1-q^n)}{1-q}" therefore "S_n=\\frac{1-e^{-n}}{1-e^{-1}}"
C) "\\lim\\limits_{n\\to\\infty}S_n=\\frac{1}{1-e^{-1}}=\\frac{e}{e-1}" - true
D) this series is not a telescoping series
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