Question #114100

A pentagon is formed by placing an isosceles triangle on a rectangle, as shown in the figure. if the pentagon has fixed perimeter P, find the lengths of the sides of the pentagon that maximize the area of the pentagon

Expert's answer


Let a and b be sides of pentagon, a be the side of triangle.


S=ab+a234S=ab+ \frac {a^2 \sqrt{3}}{4}

3a+2b=P3a+2b=P

b=0.5P−1.5ab=0.5P-1.5 a

S=a(0.5P−1.5a)+a234S=a(0.5P-1.5a)+ \frac {a^2 \sqrt{3}}{4}


Sa/=0.5P−2a−32a=0S^/_a=0.5P-2a- \frac{ \sqrt {3}}{2}a=0


a=P4−3a=\frac {P}{4- \sqrt{3}}


b=0.5−0.534−3Pb=\frac {0.5-0.5\sqrt{3}}{4-\sqrt{3}}P


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