Given v=Ve−t/RCv = V e^{-t/RC}v=Ve−t/RC .
So, dvdt=V−1RCe−t/RC=−VRCe−t/RC\frac{dv}{dt} = V \frac{-1}{RC} e^{-t/RC} =-\frac{V}{RC} e^{-t/RC}dtdv=VRC−1e−t/RC=−RCVe−t/RC .
Now dv/dtdv/dtdv/dt at t=T is dvdt∣t=T=−VRCe−T/RC\frac{dv}{dt}|_{t=T} =-\frac{V}{RC} e^{-T/RC}dtdv∣t=T=−RCVe−T/RC
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