Question #110452
the inverse function of y=e^3x is y=1/3 lnx
1
Expert's answer
2020-04-20T11:12:15-0400

Consider the function y=e3xy=e^{3x}


Replace xx and yy to obtain,



x=e3yx=e^{3y}


Now, take log of base ee both sides to isolate the exponent as,



ln(x)=ln(e3y)ln(x)=ln(e^{3y})


Use the property of logarithm ln(ea)=aln(e^{a})=a to extract the right side of equation from log as,



ln(x)=3yln(x)=3y


Divide both sides by 33 to obtain,



y=13ln(x)y=\frac{1}{3}ln(x)

Therefore, the inverse of the function y=e3xy=e^{3x} is y=13ln(x)y=\frac{1}{3}ln(x). Hence proved.



Also, note that the function and it's inverse is symmetric about the line y=xy=x .



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