Question

∫²∫¹ x² dx

Answer 1

$\intop_0^2 \intop_0^1 x^2 dx dy = \intop_0^2 [\frac{x^3}{3}]_0^1 dy = \intop_0^2 [\frac{1}{3}] dy = \frac{1}{3} \intop_0^2 1 dy = \frac{1}{3} [y]_0^2 = \frac{1}{3} (2) = \frac{2}{3}$ .