Answer to Question #110052 in Calculus for Nimra

Question

∫³∫¹ cosx dx

Answer 1

$$\displaystyle\int_{1}^3\cos{x}dx=[\sin{x}]\begin{matrix} 3 \\ 1 \end{matrix}=\sin{3}-\sin{1}=2\sin{1}\cos{2}$$