limx→4x−4x2−16=limx→4x−4(x−4)(x+4)=\lim_{x\to 4}\frac{x-4}{x^2-16}=\lim_{x\to 4}\frac{x-4}{(x-4)(x+4)}=limx→4x2−16x−4=limx→4(x−4)(x+4)x−4=
=limx→41x+4=18=0.125.=\lim_{x\to 4}\frac{1}{x+4}=\frac{1}{8}=0.125.=limx→4x+41=81=0.125.
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