a1=5,
a2=15,
a3=125,
a4=1235,
a5=?
an+1=12…n 5a_{n+1}=12\ldots n \,5an+1=12…n5, n≥1,n \geq 1,n≥1, a1=5a_1=5a1=5 for n=0n=0n=0.
So a5=a4+1=12345a_5=a_{4+1}=12345a5=a4+1=12345
Answer: 123451234512345.
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