∫ f(x) = sin 2x
As ∫f(x)dx=sin2x\int f(x)dx=sin2x∫f(x)dx=sin2x
So f(x)=d(sin2x)dxf(x)=\frac{d(sin2x)}{dx}f(x)=dxd(sin2x)
Hence f(x)=2cos2xf(x)=2cos2xf(x)=2cos2x
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