The statement is false .
We have many counter example.
1.Define a function,
f:[0,1]→Rf:[0,1]\rightarrow Rf:[0,1]→R , by f(x)=5f(x)=5f(x)=5
Which is a constant function and is finite.
2.f:[0,1]→Rf:[0,1]\rightarrow Rf:[0,1]→R defined by f(x)=xf(x)=xf(x)=x
Which is a bounded function ,bounded by 5. Etc
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