The given function is ,
f(x,y)=(y+x)(y−x)×(1+y2)(1+x2) 
Now, we have to find the repeated limit of f(x,y) 
limx→0 (limy→0f(x,y) )=limx→0 ( -1×(1+x2) ) 
 =−1 .
limy→0 ( limx→0f(x,y) )  =limy→0 ( (1+y2)1 ) 
                                                             =1 .
No,simultaneous limit of f at (0,0) does not exist.
Because the above repeated limit are not equal.
 
                             
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