Question #105325
For all even integral values of n , lim
x-infinite (X+1)^-n exists
1
Expert's answer
2020-03-13T12:10:37-0400

In general the limit does not exist.

Case:1 If n>0n>0 .

In this case, limx(x+1)n=limx1(x+1)n\lim_{x\to \infty}(x+1)^{-n}=\lim_{x\to \infty} \frac{1}{(x+1)^n} =0=0

Hence the limit exists.

Case: 2 If n=0n=0

In this case, limx(x+1)n=1\lim_{x\to \infty}{(x+1)^{-n}}=1

Hence the limit exists.

Case:3 If n<0n<0

In this case, limx(x+1)n=\lim_{x\to \infty}(x+1)^{-n}=\infty

And the limit does not exist.


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