if f is one - one onto and differentiablw on R, then, "(f^{-1}(6))^{'}=1\/f^{'}(6)" is true because "(f^{-1}(y_o))^{'}=1\/f^{'}(x_o)" for "f(x)=x" .
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment