Question #104827
if f is one - one onto and differentiablw on R, then (f^-1)'(6)=1/f'(6) .Is the statement tue or false.
Explain why
1
Expert's answer
2020-03-10T12:52:02-0400

if f is one - one onto and differentiablw on R, then, (f1(6))=1/f(6)(f^{-1}(6))^{'}=1/f^{'}(6) is true because (f1(yo))=1/f(xo)(f^{-1}(y_o))^{'}=1/f^{'}(x_o) for f(x)=xf(x)=x .


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