Question #104696
Can the intermediate value theorem be applied to show that there is a root of the equation x^5-x^3+3x-5=0 in the given interval ]1,2[?If yes , apply it
1
Expert's answer
2020-03-05T16:59:17-0500

f(x)=x5x3+3x5=0f(x)= x^5-x^3+3x-5=0

f(1)=2f(2)=25f(1)=-2\\f(2)=25

There is a change of sign of ff when xx passes from 1 to 2, it means there will be some intermediate value of xx in [1,2] for which f(x)=0f(x) =0 which means there is a root in [1,2].


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