Can the intermediate value theorem be applied to show that there is a root of the equation x^5-x^3+3x-5=0 in the given interval ]1,2[?If yes , apply it
Expert's answer
f(x)=x5−x3+3x−5=0
f(1)=−2f(2)=25
There is a change of sign of f when x passes from 1 to 2, it means there will be some intermediate value of x in [1,2] for which f(x)=0 which means there is a root in [1,2].
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