Question #104285
Y = 3e^2x + 4 sin x
1
Expert's answer
2020-03-03T11:19:13-0500

y′=(3e2x+4sin⁡x)′=6e2x+4cos⁡xy'=\left(3e^{2x}+4\sin x\right)'=6e^{2x}+4\cos x


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Canada #334539 on Jan 2023