Answer to Question #103884 in Calculus for BIVEK SAH

Question #103884
Check whether the function, ,f defined below, is uniformly continuous or not:

f(x)=x^(1/2), x∈[1,2]
1
Expert's answer
2020-03-04T12:35:58-0500

"f(x)=\\sqrt {x}\\ , \\ \\ \\ x\\epsilon" "[1,2]"

This function is valid for positive x and in the domain [1,2] the entity inside the square root function is positive so this function is continuous over the domain [1,2]

It can be also checked using graph



so from the graph we can see that the function is continuous for x>0


For function to be uniform continuous then the function must satisfy the two condition :

1) function is continuous in [a,b] and interval is closed

2) limit at x=a and x=b is finite

so the above two conditions are fulfilled hence the function is uniformly continuous


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