"f(x)=\\sqrt {x}\\ , \\ \\ \\ x\\epsilon" "[1,2]"
This function is valid for positive x and in the domain [1,2] the entity inside the square root function is positive so this function is continuous over the domain [1,2]
It can be also checked using graph
so from the graph we can see that the function is continuous for x>0
For function to be uniform continuous then the function must satisfy the two condition :
1) function is continuous in [a,b] and interval is closed
2) limit at x=a and x=b is finite
so the above two conditions are fulfilled hence the function is uniformly continuous
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