∫x(4+22)1/2dx\frac{x}{(4+2^2)^{1/2}}dx(4+22)1/2xdx
=1(4+22)1/2∫xdx=\frac{1}{(4+2^2)^{1/2}} \int xdx=(4+22)1/21∫xdx
=x22⋅1(4+22)1/2+C=\frac{x^2}{2} \cdot \frac{1}{(4+2^2)^{1/2}}+C=2x2⋅(4+22)1/21+C
=x22⋅12⋅21/2+C=\frac{x^2}{2}\cdot \frac{1}{2 \cdot 2^{1/2}}+C=2x2⋅2⋅21/21+C
=x24⋅21/2+C=\frac{x^2}{4 \cdot 2^{1/2}}+C=4⋅21/2x2+C
Answer: x24⋅21/2+C\frac{x^2}{4 \cdot 2^{1/2}}+C4⋅21/2x2+C
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