Let X be those minutes we will use for a month and n(1, 2, or 3) is number deal, so the fomula is
TotalCost=50+(n−2)(n−3)[X∗2]/2−−(n−1)(n−3)[250+2.50max(0,X−24∗50)]++(n−1)(n−2)[400+1.50max(0,X−24∗120)]/2
If Deal 1 (n=1) : Total1=R50+(n−2)(n−3)[X∗R2];
If Deal 2 (n=2):Total2=R50 +R250+R2.50∗max(0,X−24∗R50)];
If Deal 3 (n=3):Total3=R50+R400+R1.50∗max(0,X−24∗120);
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