Answer to Question #102276 in Calculus for Nimra

Question

f(x)=secx²+3x²+yx²

Answer 1

$f(x,y)=2xsec(x^2)+3x^2+yx^2$

$\frac{\partial f(x,y)}{\partial x}=2x\frac{sin(x^2)}{cos^2(x^2)}+x(6+2y)$

$\frac{\partial f(x,y)}{\partial y}=x^2$