Answer to Question #102274 in Calculus for Nimra

Question

f(y)=sinx+cscx²y+2xy

Answer 1

$f(x,y)=sin(x)+csc(x^2y)+2xy$

$\frac{\partial f}{\partial x}=cos(x)-2xy\frac{cos(x^2y)}{sin^2(x^2y)}+2y$

$\frac{\partial f}{\partial y}=-x^2\frac{cos(x^2y)}{sin^2(x^2y)}+2x$