First let's find the intersection points of these curves
y2−2=y ⟺ y2−2−y=0y^2-2=y\iff y^2-2-y=0y2−2=y⟺y2−2−y=0
y=−1;y=2y=-1;\quad y=2y=−1;y=2
The area between these curves can be found as a Riemann integral
S=∣∫−12(y2−y−2)dy∣=∣(y33−y22−2y)−12∣=92S=\left|\int\limits_{-1}^2(y^2-y-2)dy\right|=\left|\left(\frac{y^3}{3}-\frac{y^2}{2}-2y\right)_{-1}^2\right|=\frac{9}{2}S=∣∣−1∫2(y2−y−2)dy∣∣=∣∣(3y3−2y2−2y)−12∣∣=29
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