"det\\begin{bmatrix}\n 2 & -3&5 \\\\\n 3 & 1&-2\\\\\n 1&-7&12\n\\end{bmatrix}=2*1*12+3*5*(-7)+(-3)*(-2)*1-\\\\-\n1*1*5-2*(-7)*(-2)-3*(-3)*12=0."
So, the vectors are linearly dependent.
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