det[2−3531−21−712]=2∗1∗12+3∗5∗(−7)+(−3)∗(−2)∗1−−1∗1∗5−2∗(−7)∗(−2)−3∗(−3)∗12=0.det\begin{bmatrix} 2 & -3&5 \\ 3 & 1&-2\\ 1&-7&12 \end{bmatrix}=2*1*12+3*5*(-7)+(-3)*(-2)*1-\\- 1*1*5-2*(-7)*(-2)-3*(-3)*12=0.det⎣⎡231−31−75−212⎦⎤=2∗1∗12+3∗5∗(−7)+(−3)∗(−2)∗1−−1∗1∗5−2∗(−7)∗(−2)−3∗(−3)∗12=0.
So, the vectors are linearly dependent.
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