Question #9450

Sub 23
ques: 5

Find an equation of the hyperbola described:

Foci (0, -8) and (0, 8); difference of focal radii 10

Expert's answer

As we see from the focuses situation, the main axis for hyperbola is an OY axis

Knowing, that the difference between the focal radii of hyperbola equals 2a2a, we can calculate it:


2a=10,a=52a = 10, \quad a = 5


Now, as we know


c2=a2+b2,or64=25+b2c^2 = a^2 + b^2, \quad \text{or} \quad 64 = 25 + b^2b2=39b^2 = 39


Now, keeping in mind, that main axis is OY, we can write down the equation:


y225x239=1\frac{y^2}{25} - \frac{x^2}{39} = 1

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