I'll use invariants.
2 x 2 + 7 y 2 − 4 x y + 3 y − 1 = 0 a 11 = 2 , a 22 = 7 , a 12 = − 2 , a 13 = 0 , a 23 = 1.5 , a 33 = − 1 I 2 = ∣ 2 − 2 − 2 7 ∣ = 10 > 0 I 3 = ∣ 2 − 2 0 − 2 7 1.5 0 1.5 − 1 ∣ = − 14 − 2 ∗ 2.25 + 4 = − 14.5 I 1 = t r ( 2 − 2 − 2 7 ) = 9 I 2 > 0 , I 1 I 3 < 0 ⟹ E l l i p s e 2x^2+7y^2-4xy+3y-1=0 \\ \\
a_{11} = 2, a_{22} = 7, a_{12} = -2, a_{13} = 0, a_{23} = 1.5, a_{33} = -1 \\ \\I_2 = \begin{vmatrix}
2 & -2 \\
-2 & 7
\end{vmatrix} = 10 > 0 \\ \\I_3 = \begin{vmatrix}
2 & -2 & 0 \\
-2 & 7 & 1.5\\
0 & 1.5 & -1
\end{vmatrix} = -14 - 2*2.25 + 4 = -14.5 \\ \\ I_1 = tr\begin{pmatrix}
2 & -2 \\
-2 & 7
\end{pmatrix} = 9 \\ \\ I_2 > 0, I_1I_3 < 0 \implies Ellipse 2 x 2 + 7 y 2 − 4 x y + 3 y − 1 = 0 a 11 = 2 , a 22 = 7 , a 12 = − 2 , a 13 = 0 , a 23 = 1.5 , a 33 = − 1 I 2 = ∣ ∣ 2 − 2 − 2 7 ∣ ∣ = 10 > 0 I 3 = ∣ ∣ 2 − 2 0 − 2 7 1.5 0 1.5 − 1 ∣ ∣ = − 14 − 2 ∗ 2.25 + 4 = − 14.5 I 1 = t r ( 2 − 2 − 2 7 ) = 9 I 2 > 0 , I 1 I 3 < 0 ⟹ Ell i p se
Answer: b
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