a) If two different equations of the line are
and
where t1 and t2 are parameters.
Since there is only one line containing given point and parallel to given non-zero vector, it is enough to prove that both lines contains the same point and their directional vectors are parallel and therefore have proportional coordinates:
If equations (1) and (2) represent the same line, point (x2, y2, z2) should satisfy equation (1)
so system
should have unique solution t1.
In general to prove that two equations represent the same curve it is enough to find a bijection between t1 and t2, so that corresponding point of curves are the same.
In case of ф straight line if a bijection exists, then it can be found from the equation
or
"t_2=(x_1-x_2)\/d+at_1\/d"and should satisfy equations
b)The line of intersection L belongs to two planes Π1 and Π2, hence L is orthogonal to normal vectors n1 and n2.
Since planes Π1 and Π2 are not parallel, their normal vectors are not parallel either.
A direction of vector orthogonal to two given linearly independent vectors is uniquely determined and the vector m = n1×n2 is orthogonal to vectors n1 and n2, hence a directional vector of L is parallel to m.
Another geometric description is as follows:
Vector m = n1×n2 is orthogonal to vectors n1 and n2, hence m is parallel to Π1 and Π2, therefore m is parallel to the line L of intersection of planes.
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