Answer on Question #83111 – Math – Analytic Geometry
Question
If a vector X is represented as [xsinθi+ysinθj] then another vector Y which is normal to X can be represented as
Solution
Normal vector: Y=[i,kj].
X⋅Y=0→xsinθ+kysinθ=0→k=−yx.Y=[1,−yx].
Answer: Y=[1,−yx].
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