Question

Determine the gradient of a straight line passing through the point (1,6) and (-3,-3)

Answer 1

Answer on Question #83037 - Math - Analytic Geometry

Question

Determine the gradient of a straight line passing through the point $(1,6)$ and $(-3, - 3)$ .

Solution

We have to find the straight line passing through the points $(1,6)$ and $(-3, - 3)$ .

The equation of a line passing through the points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given by

$$\frac {y - y _ {1}}{x - x _ {1}} = \frac {y _ {2} - y _ {1}}{x _ {2} - x _ {1}}$$

Here $k = \frac{y_2 - y_1}{x_2 - x_1}$ is the gradient of the line. Substituting the given values we get

$$k = \frac {- 3 - 6}{- 3 - 1} = \frac {9}{4} = 2. 2 5$$

Answer: the gradient of a straight line is 2.25.

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