Question #83012

A line AB passes through the point P(3,-2) with gradient -1/2, determine the equation of the line CD through P perpendicular to AB.

Expert's answer

Answer on Question # 83012, Math / Analytic Geometry

Question 1. A line ABAB passes through the point P(3,2)P(3, -2) with gradient 1/2-1/2, determine the equation of the line CDCD through PP perpendicular to ABAB.

Proof. Gradient of ABAB is tanα=1/2\tan\alpha = -1/2. We have ABCDAB \perp CD so gradient of CDCD is tan(1/2+π/2)=cotα=1/tanα=2\tan(1/2 + \pi/2) = -\cot\alpha = -1/\tan\alpha = 2. So equation of the line CDCD is y=2x+cy = 2x + c. And P(3,2)CDP(3, -2) \in CD then 2=6+c-2 = 6 + c, c=8c = -8. So the answer is y=2x8y = 2x - 8.

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